Diffucult: I am confused by the note where it says that a^(-1)Na=N does not mean that a^(-1)na=n for each n in N, all it means is that a^(-1)na=n_1 for some n_1 in N.
Interesting: It was interesting to see it mentioned that just because Na=aN doesn't mean that a commutes. That is something I was noticing in the homework.
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